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2v^2-2v-60=0
a = 2; b = -2; c = -60;
Δ = b2-4ac
Δ = -22-4·2·(-60)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*2}=\frac{-20}{4} =-5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*2}=\frac{24}{4} =6 $
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